\( \int_1^b2x^3dx=2\cdot\frac{1}{4}x^4|_1^b=\frac{1}{2}(b^4-1)=40.5 \)
\(b^4-1=81\)
\(b^4=82\)
\(b=3.009....\approx 3.0\)
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\( \int_1^b2x^3dx=2\cdot\frac{1}{4}x^4|_1^b=\frac{1}{2}(b^4-1)=40.5 \)
\(b^4-1=81\)
\(b^4=82\)
\(b=3.009....\approx 3.0\)