\(\frac{1}{\lambda^2} + \frac{1}{4\lambda^2}-5 = 0\)
\(\frac{1}{\lambda^2} + \frac{1}{4\lambda^2}= 5\)
\(\frac{4}{4\lambda^2} + \frac{1}{4\lambda^2}= 5\)
\(\frac{5}{4\lambda^2} = 5\)
\(\frac{1}{4\lambda^2} = 1\)
\(\frac{1}{4} = \lambda^2\)
\(\pm \frac{1}{2} = \lambda\)
Student, Punkte: 350