\(P(X\geq 2|X<3)=\frac{P(X\geq 2\ \land \ X<3)}{P(X<3)}=\frac{P(X\leq 3)-P(X\leq 2)}{P(X\leq 3)}=\frac{\frac{26}{27}-\frac{7}{8}}{\frac{26}{27}}=\frac{19}{208}\)
\(P(X\leq 2)=3\int\limits_1^2 x^{-4}\,\mathrm dx=-(2^{-3}-1)=\frac{7}{8}\)
Grüße
Student, Punkte: 4.59K