wenn \(f(x) = x^{1 \over 2} \text { ist, dann ist } f(1) = 1^{1 \over2} = \sqrt1 = 1\)
\(f´(x) = {1 \over 2} x^{-1 \over 2} \Rightarrow f´(1) = {1 \over 2} 1^{-1 \over 2} = {1 \over 2}*{1 \over \sqrt 1} = {1 \over 2}\)
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