\(4x^{2}+24x+20 = 0\)|:4
\(x^{2}+6x+5 = 0\)
\(\Rightarrow p = 6, q = 5\)
pq-Formel:
\(x_{1/2} = -\frac{6}{2} +/- \sqrt{(\frac{6}{2})^{2} - 5}\)
\(x_{1/2} = -3 +/- \sqrt{9-5}\)
\(x_{1/2} = -3 +/- 2\)
\(\Rightarrow x_{1} = -1\) und \(x_{2} = -5\)
─ MarcSchulz 04.06.2020 um 21:09