Moin kundi.
\(-n+\dfrac{1}{\lambda}\displaystyle\sum X_i=0\)
\(\Leftrightarrow \dfrac{1}{\lambda}\displaystyle\sum X_i=n\)
\(\Leftrightarrow \displaystyle\sum X_i=n\cdot \lambda\)
\(\Leftrightarrow \dfrac{1}{n}\displaystyle\sum X_i=\lambda\)
Grüße
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