Nein, \(32\cdot 4^{0.5x-2} \not\equiv 2^{2x}\).
\(32\cdot 4^{0.5x-2} = 32 \cdot 4^{0.5x} \cdot 4^{-2} = 2\cdot 4^{0.5x} = 2\cdot 2^x = 2^{x+1}\)
Sonstiger Berufsstatus, Punkte: 16.5K
f(x)=32*4 hoch 0,5x-2
Nein, \(32\cdot 4^{0.5x-2} \not\equiv 2^{2x}\).
\(32\cdot 4^{0.5x-2} = 32 \cdot 4^{0.5x} \cdot 4^{-2} = 2\cdot 4^{0.5x} = 2\cdot 2^x = 2^{x+1}\)