\(a + a\bar c+\bar b+\bar ab\): \(a\) absorbiert \(a\bar c\)
\(a + \bar b+ \bar ab\): Distributivgesetz: \(\bar b + \bar ab = (\bar b + \bar a)(\bar b + b) = (\bar b + \bar a)\cdot 1\)
\(a + \bar b+ \bar a\) : Es gilt \(a + \bar a = 1\)
\(1 + \bar b = 1\)
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